Stanford Encyclopedia of Philosophy

Supplement to Actualism

Proof of NE in SQML

Theorem (NE): ∀x□∃y(y=x)

Proof:

(1) x = x identity axiom
(2) ∀y(y ≠ x) → x ≠ x quantifier axiom
(3) x = x → ¬∀y(y ≠ x) from (2), by propositional logic
(4) x = x → ∃y(y = x) from (3), by definition of ∃ and propositional logic
(5) ∃y(y = x) from (1) and (4), by MP
(6) □∃y(y = x) from (5), by RN
(7) ∀x□∃y(y = x) from (6), by GEN